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4925999232041 is a prime number
BaseRepresentation
bin100011110101110110001…
…1011110011010000101001
3122102220212100121121122112
41013223230123303100221
51121201421300411131
614250550043132105
71015614565420016
oct107535433632051
918386770547575
104925999232041
11162a117167298
12676837214035
1329969ab197c4
141305c369a70d
158820ac8802b
hex47aec6f3429

4925999232041 has 2 divisors, whose sum is σ = 4925999232042. Its totient is φ = 4925999232040.

The previous prime is 4925999231957. The next prime is 4925999232079. The reversal of 4925999232041 is 1402329995294.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2699251843600 + 2226747388441 = 1642940^2 + 1492229^2 .

It is a cyclic number.

It is not a de Polignac number, because 4925999232041 - 210 = 4925999231017 is a prime.

It is a super-2 number, since 2×49259992320412 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4925999232941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2462999616020 + 2462999616021.

It is an arithmetic number, because the mean of its divisors is an integer number (2462999616021).

Almost surely, 24925999232041 is an apocalyptic number.

It is an amenable number.

4925999232041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4925999232041 is an equidigital number, since it uses as much as digits as its factorization.

4925999232041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12597120, while the sum is 59.

The spelling of 4925999232041 in words is "four trillion, nine hundred twenty-five billion, nine hundred ninety-nine million, two hundred thirty-two thousand, forty-one".