Base | Representation |
---|---|
bin | 1001001011011110… |
… | …10000100101101111 |
3 | 110201110010002010222 |
4 | 10211233100211233 |
5 | 40043044104012 |
6 | 2133002321555 |
7 | 233060161256 |
oct | 44557204557 |
9 | 13643102128 |
10 | 4928113007 |
11 | 20a9878274 |
12 | b564b92bb |
13 | 606cac1cc |
14 | 34a70b79d |
15 | 1dc9a6972 |
hex | 125bd096f |
4928113007 has 2 divisors, whose sum is σ = 4928113008. Its totient is φ = 4928113006.
The previous prime is 4928112989. The next prime is 4928113027. The reversal of 4928113007 is 7003118294.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4928113007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4928113027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2464056503 + 2464056504.
It is an arithmetic number, because the mean of its divisors is an integer number (2464056504).
Almost surely, 24928113007 is an apocalyptic number.
4928113007 is a deficient number, since it is larger than the sum of its proper divisors (1).
4928113007 is an equidigital number, since it uses as much as digits as its factorization.
4928113007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 35.
The square root of 4928113007 is about 70200.5199909516. The cubic root of 4928113007 is about 1701.7413537398.
The spelling of 4928113007 in words is "four billion, nine hundred twenty-eight million, one hundred thirteen thousand, seven".
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