49296725353 has 4 divisors (see below), whose sum is σ = 49297193428. Its totient is φ = 49296257280.

The previous prime is 49296725327. The next prime is 49296725363. The reversal of 49296725353 is 35352769294.

49296725353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35352769294 = 2 ⋅17676384647.

It can be written as a sum of positive squares in 2 ways, for example, as 26818320169 + 22478405184 = 163763^2 + 149928^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-49296725353 is a prime.

It is a super-2 number, since 2×49296725353² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49296725294 and 49296725303.

It is not an unprimeable number, because it can be changed into a prime (49296725363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6013 + ... + 314053.

It is an arithmetic number, because the mean of its divisors is an integer number (12324298357).

Almost surely, 2^49296725353 is an apocalyptic number.

It is an amenable number.

49296725353 is a deficient number, since it is larger than the sum of its proper divisors (468075).

49296725353 is a wasteful number, since it uses less digits than its factorization.

49296725353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 468074.

The product of its digits is 12247200, while the sum is 55.

The spelling of 49296725353 in words is "forty-nine billion, two hundred ninety-six million, seven hundred twenty-five thousand, three hundred fifty-three".