Base | Representation |
---|---|
bin | 10110011011001100101100… |
… | …00101010111110101101011 |
3 | 20110121021120101001022100001 |
4 | 23031212112011113311223 |
5 | 22430421100101004024 |
6 | 252514032515123431 |
7 | 13246515016563535 |
oct | 1315462605276553 |
9 | 213537511038301 |
10 | 49313037516139 |
11 | 147925a60a9321 |
12 | 56452445a3577 |
13 | 2169279361b37 |
14 | c26a99a36855 |
15 | 5a7b2a46a244 |
hex | 2cd996157d6b |
49313037516139 has 2 divisors, whose sum is σ = 49313037516140. Its totient is φ = 49313037516138.
The previous prime is 49313037516137. The next prime is 49313037516187. The reversal of 49313037516139 is 93161573031394.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49313037516139 - 21 = 49313037516137 is a prime.
It is a super-3 number, since 3×493130375161393 (a number of 42 digits) contains 333 as substring.
Together with 49313037516137, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 49313037516139.
It is not a weakly prime, because it can be changed into another prime (49313037516137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24656518758069 + 24656518758070.
It is an arithmetic number, because the mean of its divisors is an integer number (24656518758070).
Almost surely, 249313037516139 is an apocalyptic number.
49313037516139 is a deficient number, since it is larger than the sum of its proper divisors (1).
49313037516139 is an equidigital number, since it uses as much as digits as its factorization.
49313037516139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5511240, while the sum is 55.
The spelling of 49313037516139 in words is "forty-nine trillion, three hundred thirteen billion, thirty-seven million, five hundred sixteen thousand, one hundred thirty-nine".
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