Base | Representation |
---|---|
bin | 100011111001001111101… |
… | …1010111100000101000111 |
3 | 122110121200221211110120121 |
4 | 1013302133122330011013 |
5 | 1121311343024014413 |
6 | 14254154141442411 |
7 | 1016263462265245 |
oct | 107623732740507 |
9 | 18417627743517 |
10 | 4933297094983 |
11 | 1632221665784 |
12 | 678133270407 |
13 | 29a291a528ba |
14 | 130ab69d1795 |
15 | 884d67dcb8d |
hex | 47c9f6bc147 |
4933297094983 has 4 divisors (see below), whose sum is σ = 4933437197128. Its totient is φ = 4933156992840.
The previous prime is 4933297094933. The next prime is 4933297095011. The reversal of 4933297094983 is 3894907923394.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4933297094983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4933297094923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69998241 + ... + 70068682.
It is an arithmetic number, because the mean of its divisors is an integer number (1233359299282).
Almost surely, 24933297094983 is an apocalyptic number.
4933297094983 is a deficient number, since it is larger than the sum of its proper divisors (140102145).
4933297094983 is a wasteful number, since it uses less digits than its factorization.
4933297094983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140102144.
The product of its (nonzero) digits is 317447424, while the sum is 70.
The spelling of 4933297094983 in words is "four trillion, nine hundred thirty-three billion, two hundred ninety-seven million, ninety-four thousand, nine hundred eighty-three".
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