Base | Representation |
---|---|
bin | 1110010111000010110… |
… | …10100111000100110111 |
3 | 1202011120110102120102011 |
4 | 13023201122213010313 |
5 | 31040444434334033 |
6 | 1014400224225051 |
7 | 50435053554550 |
oct | 7134132470467 |
9 | 1664513376364 |
10 | 493408121143 |
11 | 180287026333 |
12 | 7b76146b187 |
13 | 376b356aa42 |
14 | 19c49983327 |
15 | cc7c083ccd |
hex | 72e16a7137 |
493408121143 has 8 divisors (see below), whose sum is σ = 564580172288. Its totient is φ = 422407364184.
The previous prime is 493408121137. The next prime is 493408121203. The reversal of 493408121143 is 341121804394.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 493408121143 - 25 = 493408121111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 493408121096 and 493408121105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (493408121113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42817371 + ... + 42828892.
It is an arithmetic number, because the mean of its divisors is an integer number (70572521536).
Almost surely, 2493408121143 is an apocalyptic number.
493408121143 is a deficient number, since it is larger than the sum of its proper divisors (71172051145).
493408121143 is an equidigital number, since it uses as much as digits as its factorization.
493408121143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85647093.
The product of its (nonzero) digits is 82944, while the sum is 40.
The spelling of 493408121143 in words is "four hundred ninety-three billion, four hundred eight million, one hundred twenty-one thousand, one hundred forty-three".
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