Base | Representation |
---|---|
bin | 1110010111000011010… |
… | …10011010010010100111 |
3 | 1202011120202020000002012 |
4 | 13023201222122102213 |
5 | 31041002014404304 |
6 | 1014400453104435 |
7 | 50435134015301 |
oct | 7134152322247 |
9 | 1664522200065 |
10 | 493412263079 |
11 | 1802893a521a |
12 | 7b76292811b |
13 | 376b438b0a8 |
14 | 19c4a340971 |
15 | cc7c60116e |
hex | 72e1a9a4a7 |
493412263079 has 4 divisors (see below), whose sum is σ = 503910396384. Its totient is φ = 482914129776.
The previous prime is 493412263051. The next prime is 493412263103. The reversal of 493412263079 is 970362214394.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-493412263079 is a prime.
It is a super-2 number, since 2×4934122630792 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (493412263049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5249066582 + ... + 5249066675.
It is an arithmetic number, because the mean of its divisors is an integer number (125977599096).
Almost surely, 2493412263079 is an apocalyptic number.
493412263079 is a deficient number, since it is larger than the sum of its proper divisors (10498133305).
493412263079 is a wasteful number, since it uses less digits than its factorization.
493412263079 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10498133304.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 493412263079 in words is "four hundred ninety-three billion, four hundred twelve million, two hundred sixty-three thousand, seventy-nine".
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