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493526271041 is a prime number
BaseRepresentation
bin1110010111010000111…
…01010100010001000001
31202011212200202012121022
413023220131110101001
531041220211133131
61014420044435225
750441020042106
oct7135035242101
91664780665538
10493526271041
11180337794081
127b794b48b15
1337701b9781b
1419c5b53aaad
15cc8762137b
hex72e8754441

493526271041 has 2 divisors, whose sum is σ = 493526271042. Its totient is φ = 493526271040.

The previous prime is 493526271019. The next prime is 493526271047. The reversal of 493526271041 is 140172625394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 433880420416 + 59645850625 = 658696^2 + 244225^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-493526271041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 493526270983 and 493526271001.

It is not a weakly prime, because it can be changed into another prime (493526271047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246763135520 + 246763135521.

It is an arithmetic number, because the mean of its divisors is an integer number (246763135521).

Almost surely, 2493526271041 is an apocalyptic number.

It is an amenable number.

493526271041 is a deficient number, since it is larger than the sum of its proper divisors (1).

493526271041 is an equidigital number, since it uses as much as digits as its factorization.

493526271041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 44.

The spelling of 493526271041 in words is "four hundred ninety-three billion, five hundred twenty-six million, two hundred seventy-one thousand, forty-one".