Base | Representation |
---|---|
bin | 1110010111010001111… |
… | …00000010010011100111 |
3 | 1202011220020220100002221 |
4 | 13023220330002103213 |
5 | 31041224241331233 |
6 | 1014420533213211 |
7 | 50441145352003 |
oct | 7135074022347 |
9 | 1664806810087 |
10 | 493534323943 |
11 | 180341294371 |
12 | 7b797791207 |
13 | 3770375705b |
14 | 19c5c635703 |
15 | cc881b242d |
hex | 72e8f024e7 |
493534323943 has 2 divisors, whose sum is σ = 493534323944. Its totient is φ = 493534323942.
The previous prime is 493534323847. The next prime is 493534323967. The reversal of 493534323943 is 349323435394.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 493534323943 - 213 = 493534315751 is a prime.
It is a super-2 number, since 2×4935343239432 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (493534323343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246767161971 + 246767161972.
It is an arithmetic number, because the mean of its divisors is an integer number (246767161972).
Almost surely, 2493534323943 is an apocalyptic number.
493534323943 is a deficient number, since it is larger than the sum of its proper divisors (1).
493534323943 is an equidigital number, since it uses as much as digits as its factorization.
493534323943 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12597120, while the sum is 52.
The spelling of 493534323943 in words is "four hundred ninety-three billion, five hundred thirty-four million, three hundred twenty-three thousand, nine hundred forty-three".
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