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49365107472613 is a prime number
BaseRepresentation
bin10110011100101101101011…
…01100011111100011100101
320110210020222012212011102111
423032112311230133203211
522432244220003110423
6252554003423041021
713253340245114032
oct1316266554374345
9213706865764374
1049365107472613
111480269624a2a9
125653356740171
132171156c0097a
14c293d9232389
155a91768e060d
hex2ce5b5b1f8e5

49365107472613 has 2 divisors, whose sum is σ = 49365107472614. Its totient is φ = 49365107472612.

The previous prime is 49365107472523. The next prime is 49365107472647. The reversal of 49365107472613 is 31627470156394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40504352675809 + 8860754796804 = 6364303^2 + 2976702^2 .

It is a cyclic number.

It is not a de Polignac number, because 49365107472613 - 233 = 49356517538021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49365137472613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24682553736306 + 24682553736307.

It is an arithmetic number, because the mean of its divisors is an integer number (24682553736307).

Almost surely, 249365107472613 is an apocalyptic number.

It is an amenable number.

49365107472613 is a deficient number, since it is larger than the sum of its proper divisors (1).

49365107472613 is an equidigital number, since it uses as much as digits as its factorization.

49365107472613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22861440, while the sum is 58.

The spelling of 49365107472613 in words is "forty-nine trillion, three hundred sixty-five billion, one hundred seven million, four hundred seventy-two thousand, six hundred thirteen".