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4937103553 is a prime number
BaseRepresentation
bin1001001100100011…
…00011100011000001
3110202002000211212011
410212101203203001
540102344303203
62133523132521
7233226454624
oct44621434301
913662024764
104937103553
112103958a78
12b59514141
13608b09465
1434b9abdbb
151dd68076d
hex1264638c1

4937103553 has 2 divisors, whose sum is σ = 4937103554. Its totient is φ = 4937103552.

The previous prime is 4937103533. The next prime is 4937103559. The reversal of 4937103553 is 3553017394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2871673744 + 2065429809 = 53588^2 + 45447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4937103553 is a prime.

It is not a weakly prime, because it can be changed into another prime (4937103559) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2468551776 + 2468551777.

It is an arithmetic number, because the mean of its divisors is an integer number (2468551777).

Almost surely, 24937103553 is an apocalyptic number.

It is an amenable number.

4937103553 is a deficient number, since it is larger than the sum of its proper divisors (1).

4937103553 is an equidigital number, since it uses as much as digits as its factorization.

4937103553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 40.

The square root of 4937103553 is about 70264.5255658928. The cubic root of 4937103553 is about 1702.7755757936.

The spelling of 4937103553 in words is "four billion, nine hundred thirty-seven million, one hundred three thousand, five hundred fifty-three".