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4938041413 is a prime number
BaseRepresentation
bin1001001100101010…
…01000100001000101
3110202010210111100201
410212111020201011
540103114311123
62133555210501
7233240442124
oct44625104105
913663714321
104938041413
112104439668
12b598a6a31
136090772c6
1434bb73abb
151dd7b85ad
hex126548845

4938041413 has 2 divisors, whose sum is σ = 4938041414. Its totient is φ = 4938041412.

The previous prime is 4938041351. The next prime is 4938041431. The reversal of 4938041413 is 3141408394.

Together with next prime (4938041431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4936748644 + 1292769 = 70262^2 + 1137^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4938041413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4938041443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2469020706 + 2469020707.

It is an arithmetic number, because the mean of its divisors is an integer number (2469020707).

Almost surely, 24938041413 is an apocalyptic number.

It is an amenable number.

4938041413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4938041413 is an equidigital number, since it uses as much as digits as its factorization.

4938041413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 37.

The square root of 4938041413 is about 70271.1990291898. The cubic root of 4938041413 is about 1702.8833896143.

The spelling of 4938041413 in words is "four billion, nine hundred thirty-eight million, forty-one thousand, four hundred thirteen".