Base | Representation |
---|---|
bin | 11101011100100… |
… | …010101000001011 |
3 | 1021102120212120221 |
4 | 131130202220023 |
5 | 2002432134011 |
6 | 121004330511 |
7 | 15146052562 |
oct | 3534425013 |
9 | 1242525527 |
10 | 494021131 |
11 | 23395342a |
12 | 119543a37 |
13 | 7b4708c6 |
14 | 4987abd9 |
15 | 2d586971 |
hex | 1d722a0b |
494021131 has 2 divisors, whose sum is σ = 494021132. Its totient is φ = 494021130.
The previous prime is 494021107. The next prime is 494021137. The reversal of 494021131 is 131120494.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 494021131 - 211 = 494019083 is a prime.
It is a super-2 number, since 2×4940211312 = 488113755749038322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 494021096 and 494021105.
It is not a weakly prime, because it can be changed into another prime (494021137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247010565 + 247010566.
It is an arithmetic number, because the mean of its divisors is an integer number (247010566).
Almost surely, 2494021131 is an apocalyptic number.
494021131 is a deficient number, since it is larger than the sum of its proper divisors (1).
494021131 is an equidigital number, since it uses as much as digits as its factorization.
494021131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
The square root of 494021131 is about 22226.5861301280. The cubic root of 494021131 is about 790.5242106433.
The spelling of 494021131 in words is "four hundred ninety-four million, twenty-one thousand, one hundred thirty-one".
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