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49402519849637 is a prime number
BaseRepresentation
bin10110011101110011010111…
…01001011000101010100101
320110220211112112211211111222
423032321223221120222211
522433402330040142022
6253023112044110125
713256133332063363
oct1316715351305245
9213824475754458
1049402519849637
1114817544596959
12565a657b35345
132174839b54a76
14c2b147ca0633
155aa11613e242
hex2cee6ba58aa5

49402519849637 has 2 divisors, whose sum is σ = 49402519849638. Its totient is φ = 49402519849636.

The previous prime is 49402519849619. The next prime is 49402519849663. The reversal of 49402519849637 is 73694891520494.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49092990076321 + 309529773316 = 7006639^2 + 556354^2 .

It is a cyclic number.

It is not a de Polignac number, because 49402519849637 - 218 = 49402519587493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49402519846637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24701259924818 + 24701259924819.

It is an arithmetic number, because the mean of its divisors is an integer number (24701259924819).

It is a 1-persistent number, because it is pandigital, but 2⋅49402519849637 = 98805039699274 is not.

Almost surely, 249402519849637 is an apocalyptic number.

It is an amenable number.

49402519849637 is a deficient number, since it is larger than the sum of its proper divisors (1).

49402519849637 is an equidigital number, since it uses as much as digits as its factorization.

49402519849637 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 470292480, while the sum is 71.

The spelling of 49402519849637 in words is "forty-nine trillion, four hundred two billion, five hundred nineteen million, eight hundred forty-nine thousand, six hundred thirty-seven".