4940371261 has 4 divisors (see below), whose sum is σ = 5646138592. Its totient is φ = 4234603932.

The previous prime is 4940371253. The next prime is 4940371297. The reversal of 4940371261 is 1621730494.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1621730494 = 2 ⋅810865247.

It is a cyclic number.

It is not a de Polignac number, because 4940371261 - 2³ = 4940371253 is a prime.

It is a super-5 number, since 5×4940371261⁵ (a number of 50 digits) contains 55555 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4940371261.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4940371211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352883655 + ... + 352883668.

It is an arithmetic number, because the mean of its divisors is an integer number (1411534648).

Almost surely, 2^4940371261 is an apocalyptic number.

It is an amenable number.

4940371261 is a deficient number, since it is larger than the sum of its proper divisors (705767331).

4940371261 is an equidigital number, since it uses as much as digits as its factorization.

4940371261 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 705767330.

The product of its (nonzero) digits is 36288, while the sum is 37.

The square root of 4940371261 is about 70287.7746197730. The cubic root of 4940371261 is about 1703.1511635028.

The spelling of 4940371261 in words is "four billion, nine hundred forty million, three hundred seventy-one thousand, two hundred sixty-one".