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49403893433 = 972927174007
BaseRepresentation
bin101110000000101100…
…111001011010111001
311201112001010211010212
4232000230321122321
51302134344042213
634410144520505
73366163110506
oct560054713271
9151461124125
1049403893433
1119a522343a4
1296a9320135
13487440834b
1425694bc4ad
1514423959a8
hexb80b396b9

49403893433 has 8 divisors (see below), whose sum is σ = 49930551552. Its totient is φ = 48877589376.

The previous prime is 49403893391. The next prime is 49403893463. The reversal of 49403893433 is 33439830494.

It is a happy number.

49403893433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 49403893433 - 28 = 49403893177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (49403893463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 196916 + ... + 370922.

It is an arithmetic number, because the mean of its divisors is an integer number (6241318944).

Almost surely, 249403893433 is an apocalyptic number.

It is an amenable number.

49403893433 is a deficient number, since it is larger than the sum of its proper divisors (526658119).

49403893433 is a wasteful number, since it uses less digits than its factorization.

49403893433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177031.

The product of its (nonzero) digits is 3359232, while the sum is 50.

The spelling of 49403893433 in words is "forty-nine billion, four hundred three million, eight hundred ninety-three thousand, four hundred thirty-three".

Divisors: 1 97 2927 174007 283919 16878679 509318489 49403893433