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49412537 is a prime number
BaseRepresentation
bin1011110001111…
…1100110111001
310102222102020222
42330133212321
5100122200122
64523025425
71136666606
oct274374671
9112872228
1049412537
112598a409
121466b275
13a310bb5
1467c36ad
154510b42
hex2f1f9b9

49412537 has 2 divisors, whose sum is σ = 49412538. Its totient is φ = 49412536.

The previous prime is 49412509. The next prime is 49412551. The reversal of 49412537 is 73521494.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37994896 + 11417641 = 6164^2 + 3379^2 .

It is a cyclic number.

It is not a de Polignac number, because 49412537 - 210 = 49411513 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 49412497 and 49412506.

It is not a weakly prime, because it can be changed into another prime (49412507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24706268 + 24706269.

It is an arithmetic number, because the mean of its divisors is an integer number (24706269).

Almost surely, 249412537 is an apocalyptic number.

It is an amenable number.

49412537 is a deficient number, since it is larger than the sum of its proper divisors (1).

49412537 is an equidigital number, since it uses as much as digits as its factorization.

49412537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30240, while the sum is 35.

The square root of 49412537 is about 7029.4051668687. The cubic root of 49412537 is about 366.9546405294.

It can be divided in two parts, 494 and 12537, that added together give a palindrome (13031).

The spelling of 49412537 in words is "forty-nine million, four hundred twelve thousand, five hundred thirty-seven".