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494810249472013 is a prime number
BaseRepresentation
bin111000010000001101111110…
…1001001101010100000001101
32101212222101202001100221220111
41300200123331021222200031
51004323432342331101023
64512212405052520021
7206136601153343146
oct16040337511524015
92355871661327814
10494810249472013
11133730937172142
12475b565b480011
1318313538886cc7
148a28d2dd34acd
153c3123b99300d
hex1c206fd26a80d

494810249472013 has 2 divisors, whose sum is σ = 494810249472014. Its totient is φ = 494810249472012.

The previous prime is 494810249471999. The next prime is 494810249472073. The reversal of 494810249472013 is 310274942018494.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 310953653318884 + 183856596153129 = 17633878^2 + 13559373^2 .

It is a cyclic number.

It is not a de Polignac number, because 494810249472013 - 229 = 494809712601101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (494810249472073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247405124736006 + 247405124736007.

It is an arithmetic number, because the mean of its divisors is an integer number (247405124736007).

Almost surely, 2494810249472013 is an apocalyptic number.

It is an amenable number.

494810249472013 is a deficient number, since it is larger than the sum of its proper divisors (1).

494810249472013 is an equidigital number, since it uses as much as digits as its factorization.

494810249472013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13934592, while the sum is 58.

The spelling of 494810249472013 in words is "four hundred ninety-four trillion, eight hundred ten billion, two hundred forty-nine million, four hundred seventy-two thousand, thirteen".