Base | Representation |
---|---|
bin | 1110011010000000100… |
… | …11001001011001010011 |
3 | 1202022200101211101210102 |
4 | 13031000103021121103 |
5 | 31102230000000313 |
6 | 1015222211523015 |
7 | 50522363402201 |
oct | 7150023113123 |
9 | 1668611741712 |
10 | 495000000083 |
11 | 180a23660566 |
12 | 7bb265b946b |
13 | 378a82bc244 |
14 | 19d5b162071 |
15 | cd21bcba58 |
hex | 73404c9653 |
495000000083 has 2 divisors, whose sum is σ = 495000000084. Its totient is φ = 495000000082.
The previous prime is 495000000043. The next prime is 495000000107. The reversal of 495000000083 is 380000000594.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 495000000083 - 220 = 494998951507 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 494999999992 and 495000000055.
It is not a weakly prime, because it can be changed into another prime (495000000043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247500000041 + 247500000042.
It is an arithmetic number, because the mean of its divisors is an integer number (247500000042).
Almost surely, 2495000000083 is an apocalyptic number.
495000000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
495000000083 is an equidigital number, since it uses as much as digits as its factorization.
495000000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
The spelling of 495000000083 in words is "four hundred ninety-five billion, eighty-three", and thus it is an aban number.
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