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495017332993 = 540791551199
BaseRepresentation
bin1110011010000010101…
…01010001000100000001
31202022201121110000002001
413031001111101010001
531102243414123433
61015224031224001
750522663622361
oct7150125210401
91668647400061
10495017332993
11180a32419a87
127bb30378001
13378aba7a6c1
1419d5d5949a1
15cd234a257d
hex7341551101

495017332993 has 4 divisors (see below), whose sum is σ = 495108889600. Its totient is φ = 494925776388.

The previous prime is 495017332973. The next prime is 495017333009. The reversal of 495017332993 is 399233710594.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-495017332993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (495017332973) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45770193 + ... + 45781006.

It is an arithmetic number, because the mean of its divisors is an integer number (123777222400).

Almost surely, 2495017332993 is an apocalyptic number.

It is an amenable number.

495017332993 is a deficient number, since it is larger than the sum of its proper divisors (91556607).

495017332993 is an equidigital number, since it uses as much as digits as its factorization.

495017332993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91556606.

The product of its (nonzero) digits is 5511240, while the sum is 55.

The spelling of 495017332993 in words is "four hundred ninety-five billion, seventeen million, three hundred thirty-two thousand, nine hundred ninety-three".

Divisors: 1 5407 91551199 495017332993