Base | Representation |
---|---|
bin | 101110001000000011… |
… | …011000110111101101 |
3 | 11201211122012222000101 |
4 | 232020003120313231 |
5 | 1302412432324213 |
6 | 34430312231101 |
7 | 3402221336236 |
oct | 561003306755 |
9 | 151748188011 |
10 | 49527229933 |
11 | 1a005914995 |
12 | 972269b491 |
13 | 4893b2cb1c |
14 | 257ba2608d |
15 | 144d109bdd |
hex | b880d8ded |
49527229933 has 2 divisors, whose sum is σ = 49527229934. Its totient is φ = 49527229932.
The previous prime is 49527229853. The next prime is 49527229937. The reversal of 49527229933 is 33992272594.
49527229933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25908765444 + 23618464489 = 160962^2 + 153683^2 .
It is a cyclic number.
It is not a de Polignac number, because 49527229933 - 229 = 48990359021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49527229937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24763614966 + 24763614967.
It is an arithmetic number, because the mean of its divisors is an integer number (24763614967).
Almost surely, 249527229933 is an apocalyptic number.
It is an amenable number.
49527229933 is a deficient number, since it is larger than the sum of its proper divisors (1).
49527229933 is an equidigital number, since it uses as much as digits as its factorization.
49527229933 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7348320, while the sum is 55.
The spelling of 49527229933 in words is "forty-nine billion, five hundred twenty-seven million, two hundred twenty-nine thousand, nine hundred thirty-three".
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