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495381957253 = 2917082136457
BaseRepresentation
bin1110011010101110001…
…00001100101010000101
31202100200000112211112021
413031113010030222011
531104020240113003
61015324134323141
750535012106021
oct7152704145205
91670600484467
10495381957253
111810aa222647
12800124b94b1
13379394841c1
1419d95b8b381
15cd454c92bd
hex735710ca85

495381957253 has 4 divisors (see below), whose sum is σ = 512464093740. Its totient is φ = 478299820768.

The previous prime is 495381957251. The next prime is 495381957289. The reversal of 495381957253 is 352759183594.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 119150613124 + 376231344129 = 345182^2 + 613377^2 .

It is a cyclic number.

It is not a de Polignac number, because 495381957253 - 21 = 495381957251 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 495381957191 and 495381957200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (495381957251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8541068200 + ... + 8541068257.

It is an arithmetic number, because the mean of its divisors is an integer number (128116023435).

Almost surely, 2495381957253 is an apocalyptic number.

It is an amenable number.

495381957253 is a deficient number, since it is larger than the sum of its proper divisors (17082136487).

495381957253 is a wasteful number, since it uses less digits than its factorization.

495381957253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17082136486.

The product of its digits is 40824000, while the sum is 61.

The spelling of 495381957253 in words is "four hundred ninety-five billion, three hundred eighty-one million, nine hundred fifty-seven thousand, two hundred fifty-three".

Divisors: 1 29 17082136457 495381957253