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4954040105431 = 6472197654349
BaseRepresentation
bin100100000010111001111…
…0011001111100111010111
3122112121020120110120112211
41020011303303033213113
51122131333231333211
614311504332254251
71020626506050334
oct110056363174727
918477216416484
104954040105431
11163aaa654051a
12680162011387
1329c219348791
14131ac384998b
1588cec8c4e21
hex48173ccf9d7

4954040105431 has 4 divisors (see below), whose sum is σ = 4954048407000. Its totient is φ = 4954031803864.

The previous prime is 4954040105369. The next prime is 4954040105453. The reversal of 4954040105431 is 1345010404594.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4954040105431 - 227 = 4953905887703 is a prime.

It is a super-3 number, since 3×49540401054313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4954040105471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3179956 + ... + 4474393.

It is an arithmetic number, because the mean of its divisors is an integer number (1238512101750).

Almost surely, 24954040105431 is an apocalyptic number.

4954040105431 is a deficient number, since it is larger than the sum of its proper divisors (8301569).

4954040105431 is an equidigital number, since it uses as much as digits as its factorization.

4954040105431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8301568.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 4954040105431 in words is "four trillion, nine hundred fifty-four billion, forty million, one hundred five thousand, four hundred thirty-one".

Divisors: 1 647219 7654349 4954040105431