4961207 has 2 divisors, whose sum is σ = 4961208. Its totient is φ = 4961206.

The previous prime is 4961183. The next prime is 4961213. The reversal of 4961207 is 7021694.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4961207 - 2⁸ = 4960951 is a prime.

It is a super-2 number, since 2×4961207² = 49227149793698, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4961207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4961237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2480603 + 2480604.

It is an arithmetic number, because the mean of its divisors is an integer number (2480604).

Almost surely, 2^4961207 is an apocalyptic number.

4961207 is a deficient number, since it is larger than the sum of its proper divisors (1).

4961207 is an equidigital number, since it uses as much as digits as its factorization.

4961207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 29.

The square root of 4961207 is about 2227.3767081480. The cubic root of 4961207 is about 170.5542120274.

The spelling of 4961207 in words is "four million, nine hundred sixty-one thousand, two hundred seven".