Base | Representation |
---|---|
bin | 1011110101001… |
… | …1000110001001 |
3 | 10110101010112221 |
4 | 2331103012021 |
5 | 100200422213 |
6 | 4531334041 |
7 | 1141535506 |
oct | 275230611 |
9 | 113333487 |
10 | 49623433 |
11 | 26013902 |
12 | 14751321 |
13 | a385ba2 |
14 | 683a4ad |
15 | 455338d |
hex | 2f53189 |
49623433 has 2 divisors, whose sum is σ = 49623434. Its totient is φ = 49623432.
The previous prime is 49623403. The next prime is 49623451. The reversal of 49623433 is 33432694.
49623433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33965584 + 15657849 = 5828^2 + 3957^2 .
It is a cyclic number.
It is not a de Polignac number, because 49623433 - 217 = 49492361 is a prime.
It is not a weakly prime, because it can be changed into another prime (49623403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24811716 + 24811717.
It is an arithmetic number, because the mean of its divisors is an integer number (24811717).
Almost surely, 249623433 is an apocalyptic number.
It is an amenable number.
49623433 is a deficient number, since it is larger than the sum of its proper divisors (1).
49623433 is an equidigital number, since it uses as much as digits as its factorization.
49623433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 46656, while the sum is 34.
The square root of 49623433 is about 7044.3901794265. The cubic root of 49623433 is about 367.4759618380.
The spelling of 49623433 in words is "forty-nine million, six hundred twenty-three thousand, four hundred thirty-three".
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