Base | Representation |
---|---|
bin | 101110001101111001… |
… | …001000010110010011 |
3 | 11202002110120120022210 |
4 | 232031321020112103 |
5 | 1303113023012430 |
6 | 34444132203203 |
7 | 3404521163244 |
oct | 561571102623 |
9 | 152073516283 |
10 | 49625204115 |
11 | 1a056152393 |
12 | 974b469503 |
13 | 48ab214506 |
14 | 258aa4accb |
15 | 1456a0e2b0 |
hex | b8de48593 |
49625204115 has 64 divisors (see below), whose sum is σ = 83081088000. Its totient is φ = 25262544384.
The previous prime is 49625204113. The next prime is 49625204117. The reversal of 49625204115 is 51140252694.
49625204115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (49625204113) and next prime (49625204117).
It is not a de Polignac number, because 49625204115 - 21 = 49625204113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (49625204113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14108337 + ... + 14111853.
It is an arithmetic number, because the mean of its divisors is an integer number (1298142000).
Almost surely, 249625204115 is an apocalyptic number.
49625204115 is a deficient number, since it is larger than the sum of its proper divisors (33455883885).
49625204115 is a wasteful number, since it uses less digits than its factorization.
49625204115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3916.
The product of its (nonzero) digits is 86400, while the sum is 39.
The spelling of 49625204115 in words is "forty-nine billion, six hundred twenty-five million, two hundred four thousand, one hundred fifteen".
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