Base | Representation |
---|---|
bin | 101110001110001011… |
… | …010000000001010101 |
3 | 11202002210111220010101 |
4 | 232032023100001111 |
5 | 1303120232013013 |
6 | 34444422054101 |
7 | 3404606435554 |
oct | 561613200125 |
9 | 152083456111 |
10 | 49629954133 |
11 | 1a0588a7121 |
12 | 9750b7a331 |
13 | 48ac1b8586 |
14 | 258b525d9b |
15 | 145714b8dd |
hex | b8e2d0055 |
49629954133 has 2 divisors, whose sum is σ = 49629954134. Its totient is φ = 49629954132.
The previous prime is 49629954089. The next prime is 49629954193. The reversal of 49629954133 is 33145992694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49629591729 + 362404 = 222777^2 + 602^2 .
It is a cyclic number.
It is not a de Polignac number, because 49629954133 - 213 = 49629945941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49629954193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24814977066 + 24814977067.
It is an arithmetic number, because the mean of its divisors is an integer number (24814977067).
Almost surely, 249629954133 is an apocalyptic number.
It is an amenable number.
49629954133 is a deficient number, since it is larger than the sum of its proper divisors (1).
49629954133 is an equidigital number, since it uses as much as digits as its factorization.
49629954133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6298560, while the sum is 55.
The spelling of 49629954133 in words is "forty-nine billion, six hundred twenty-nine million, nine hundred fifty-four thousand, one hundred thirty-three".
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