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49630090273 is a prime number
BaseRepresentation
bin101110001110001011…
…110001010000100001
311202002210202210212121
4232032023301100201
51303120300342043
634444425024241
73404610543511
oct561613612041
9152083683777
1049630090273
111a05898a435
129751025081
1348ac23552a
14258b55d841
151457176ded
hexb8e2f1421

49630090273 has 2 divisors, whose sum is σ = 49630090274. Its totient is φ = 49630090272.

The previous prime is 49630090271. The next prime is 49630090291. The reversal of 49630090273 is 37209003694.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39623689249 + 10006401024 = 199057^2 + 100032^2 .

It is a cyclic number.

It is not a de Polignac number, because 49630090273 - 21 = 49630090271 is a prime.

It is a super-2 number, since 2×496300902732 (a number of 22 digits) contains 22 as substring.

Together with 49630090271, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (49630090271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24815045136 + 24815045137.

It is an arithmetic number, because the mean of its divisors is an integer number (24815045137).

Almost surely, 249630090273 is an apocalyptic number.

It is an amenable number.

49630090273 is a deficient number, since it is larger than the sum of its proper divisors (1).

49630090273 is an equidigital number, since it uses as much as digits as its factorization.

49630090273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 244944, while the sum is 43.

The spelling of 49630090273 in words is "forty-nine billion, six hundred thirty million, ninety thousand, two hundred seventy-three".