Base | Representation |
---|---|
bin | 101110001111000100… |
… | …110110110110101001 |
3 | 11202010211221010011121 |
4 | 232033010312312221 |
5 | 1303133113233101 |
6 | 34450121455241 |
7 | 3405152002564 |
oct | 561704666651 |
9 | 152124833147 |
10 | 49645055401 |
11 | 1a066380a07 |
12 | 9756041521 |
13 | 48b2375036 |
14 | 258d5374db |
15 | 14586310a1 |
hex | b8f136da9 |
49645055401 has 2 divisors, whose sum is σ = 49645055402. Its totient is φ = 49645055400.
The previous prime is 49645055399. The next prime is 49645055413. The reversal of 49645055401 is 10455054694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42116890176 + 7528165225 = 205224^2 + 86765^2 .
It is a cyclic number.
It is not a de Polignac number, because 49645055401 - 21 = 49645055399 is a prime.
Together with 49645055399, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (49645055491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24822527700 + 24822527701.
It is an arithmetic number, because the mean of its divisors is an integer number (24822527701).
Almost surely, 249645055401 is an apocalyptic number.
It is an amenable number.
49645055401 is a deficient number, since it is larger than the sum of its proper divisors (1).
49645055401 is an equidigital number, since it uses as much as digits as its factorization.
49645055401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 43.
The spelling of 49645055401 in words is "forty-nine billion, six hundred forty-five million, fifty-five thousand, four hundred one".
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