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49656431879773 is a prime number
BaseRepresentation
bin10110100101001100010011…
…11110111010011001011101
320111211002221010010102010021
423102212021332322121131
523002032333030123043
6253335503324112141
713313362446530665
oct1322461176723135
9214732833112107
1049656431879773
11149051a128a264
12569b8ba695651
132192773544494
14c395540871a5
155b1a276033ed
hex2d2989fba65d

49656431879773 has 2 divisors, whose sum is σ = 49656431879774. Its totient is φ = 49656431879772.

The previous prime is 49656431879753. The next prime is 49656431879837. The reversal of 49656431879773 is 37797813465694.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44573742791449 + 5082689088324 = 6676357^2 + 2254482^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49656431879773 is a prime.

It is a super-2 number, since 2×496564318797732 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 49656431879693 and 49656431879702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49656431879753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24828215939886 + 24828215939887.

It is an arithmetic number, because the mean of its divisors is an integer number (24828215939887).

Almost surely, 249656431879773 is an apocalyptic number.

It is an amenable number.

49656431879773 is a deficient number, since it is larger than the sum of its proper divisors (1).

49656431879773 is an equidigital number, since it uses as much as digits as its factorization.

49656431879773 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5761082880, while the sum is 79.

The spelling of 49656431879773 in words is "forty-nine trillion, six hundred fifty-six billion, four hundred thirty-one million, eight hundred seventy-nine thousand, seven hundred seventy-three".