Base | Representation |
---|---|
bin | 1001010000001111… |
… | …11011101000110111 |
3 | 110211020102102022021 |
4 | 10220013323220313 |
5 | 40133320311343 |
6 | 2140552214011 |
7 | 234054311152 |
oct | 45007735067 |
9 | 13736372267 |
10 | 4968135223 |
11 | 211a423587 |
12 | b6799a307 |
13 | 612382bac |
14 | 351b68c99 |
15 | 1e12600ed |
hex | 1281fba37 |
4968135223 has 2 divisors, whose sum is σ = 4968135224. Its totient is φ = 4968135222.
The previous prime is 4968135197. The next prime is 4968135239. The reversal of 4968135223 is 3225318694.
4968135223 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4968135223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4968135223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4968135323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2484067611 + 2484067612.
It is an arithmetic number, because the mean of its divisors is an integer number (2484067612).
Almost surely, 24968135223 is an apocalyptic number.
4968135223 is a deficient number, since it is larger than the sum of its proper divisors (1).
4968135223 is an equidigital number, since it uses as much as digits as its factorization.
4968135223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 311040, while the sum is 43.
The square root of 4968135223 is about 70484.9999858126. Note that the first 4 decimals coincide. The cubic root of 4968135223 is about 1706.3356691000.
The spelling of 4968135223 in words is "four billion, nine hundred sixty-eight million, one hundred thirty-five thousand, two hundred twenty-three".
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