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4970095226113 is a prime number
BaseRepresentation
bin100100001010011000011…
…0000101010110100000001
3122121010200111000012201011
41020110300300222310001
51122412223334213423
614323121421240521
71022035410243343
oct110246060526401
918533614005634
104970095226113
1116468952042a6
126832a2a03141
132a08a7660aa4
141327a7c49293
158943c157b0d
hex48530c2ad01

4970095226113 has 2 divisors, whose sum is σ = 4970095226114. Its totient is φ = 4970095226112.

The previous prime is 4970095226099. The next prime is 4970095226137. The reversal of 4970095226113 is 3116225900794.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2564968808704 + 2405126417409 = 1601552^2 + 1550847^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4970095226113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4970095226183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485047613056 + 2485047613057.

It is an arithmetic number, because the mean of its divisors is an integer number (2485047613057).

Almost surely, 24970095226113 is an apocalyptic number.

It is an amenable number.

4970095226113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4970095226113 is an equidigital number, since it uses as much as digits as its factorization.

4970095226113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 816480, while the sum is 49.

The spelling of 4970095226113 in words is "four trillion, nine hundred seventy billion, ninety-five million, two hundred twenty-six thousand, one hundred thirteen".