Base | Representation |
---|---|
bin | 100100001010011000011… |
… | …0000101010110101000111 |
3 | 122121010200111000012210202 |
4 | 1020110300300222311013 |
5 | 1122412223334214213 |
6 | 14323121421241115 |
7 | 1022035410243503 |
oct | 110246060526507 |
9 | 18533614005722 |
10 | 4970095226183 |
11 | 164689520435a |
12 | 6832a2a0319b |
13 | 2a08a7660b29 |
14 | 1327a7c49303 |
15 | 8943c157b58 |
hex | 48530c2ad47 |
4970095226183 has 2 divisors, whose sum is σ = 4970095226184. Its totient is φ = 4970095226182.
The previous prime is 4970095226171. The next prime is 4970095226191. The reversal of 4970095226183 is 3816225900794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4970095226183 - 212 = 4970095222087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4970095226113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485047613091 + 2485047613092.
It is an arithmetic number, because the mean of its divisors is an integer number (2485047613092).
It is a 1-persistent number, because it is pandigital, but 2⋅4970095226183 = 9940190452366 is not.
Almost surely, 24970095226183 is an apocalyptic number.
4970095226183 is a deficient number, since it is larger than the sum of its proper divisors (1).
4970095226183 is an equidigital number, since it uses as much as digits as its factorization.
4970095226183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 56.
The spelling of 4970095226183 in words is "four trillion, nine hundred seventy billion, ninety-five million, two hundred twenty-six thousand, one hundred eighty-three".
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