Base | Representation |
---|---|
bin | 1110011101110000010… |
… | …00101011101001011001 |
3 | 1202111212111222112100112 |
4 | 13032320020223221121 |
5 | 31120334143211323 |
6 | 1020153512214105 |
7 | 50623245511205 |
oct | 7167010535131 |
9 | 1674774875315 |
10 | 497010522713 |
11 | 181865534a11 |
12 | 803a799a335 |
13 | 37b389abcc3 |
14 | 1a0ac199b05 |
15 | cddd46c178 |
hex | 73b822ba59 |
497010522713 has 2 divisors, whose sum is σ = 497010522714. Its totient is φ = 497010522712.
The previous prime is 497010522677. The next prime is 497010522719. The reversal of 497010522713 is 317225010794.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 419040012889 + 77970509824 = 647333^2 + 279232^2 .
It is a cyclic number.
It is not a de Polignac number, because 497010522713 - 212 = 497010518617 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (497010522719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248505261356 + 248505261357.
It is an arithmetic number, because the mean of its divisors is an integer number (248505261357).
Almost surely, 2497010522713 is an apocalyptic number.
It is an amenable number.
497010522713 is a deficient number, since it is larger than the sum of its proper divisors (1).
497010522713 is an equidigital number, since it uses as much as digits as its factorization.
497010522713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 105840, while the sum is 41.
The spelling of 497010522713 in words is "four hundred ninety-seven billion, ten million, five hundred twenty-two thousand, seven hundred thirteen".
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