Base | Representation |
---|---|
bin | 100100001010100010100… |
… | …1101111110101010000101 |
3 | 122121011120101211222201011 |
4 | 1020111011031332222011 |
5 | 1122413424221011033 |
6 | 14323215442002221 |
7 | 1022050045523413 |
oct | 110250515765205 |
9 | 18534511758634 |
10 | 4970438453893 |
11 | 1646a50a23420 |
12 | 683379946371 |
13 | 2a09307b5653 |
14 | 1327db6722b3 |
15 | 8945c354ccd |
hex | 4854537ea85 |
4970438453893 has 12 divisors (see below), whose sum is σ = 5551328992608. Its totient is φ = 4413497129160.
The previous prime is 4970438453839. The next prime is 4970438453909. The reversal of 4970438453893 is 3983548340794.
It is not a de Polignac number, because 4970438453893 - 29 = 4970438453381 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4970438453833) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 122169505 + ... + 122210182.
It is an arithmetic number, because the mean of its divisors is an integer number (462610749384).
Almost surely, 24970438453893 is an apocalyptic number.
4970438453893 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4970438453893 is a deficient number, since it is larger than the sum of its proper divisors (580890538715).
4970438453893 is a wasteful number, since it uses less digits than its factorization.
4970438453893 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244379784 (or 244379741 counting only the distinct ones).
The product of its (nonzero) digits is 313528320, while the sum is 67.
The spelling of 4970438453893 in words is "four trillion, nine hundred seventy billion, four hundred thirty-eight million, four hundred fifty-three thousand, eight hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •