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497121247369 is a prime number
BaseRepresentation
bin1110011101111101011…
…11000100000010001001
31202112011020022221000201
413032332233010002021
531121101014403434
61020212505332201
750626061611465
oct7167657040211
91675136287021
10497121247369
11181911a90a9a
1280418a97061
1337b55909156
141a0bcb7d4a5
15cde803e614
hex73bebc4089

497121247369 has 2 divisors, whose sum is σ = 497121247370. Its totient is φ = 497121247368.

The previous prime is 497121247367. The next prime is 497121247397. The reversal of 497121247369 is 963742121794.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 383408640000 + 113712607369 = 619200^2 + 337213^2 .

It is a cyclic number.

It is not a de Polignac number, because 497121247369 - 21 = 497121247367 is a prime.

It is a super-2 number, since 2×4971212473692 (a number of 24 digits) contains 22 as substring.

Together with 497121247367, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (497121247367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248560623684 + 248560623685.

It is an arithmetic number, because the mean of its divisors is an integer number (248560623685).

Almost surely, 2497121247369 is an apocalyptic number.

It is an amenable number.

497121247369 is a deficient number, since it is larger than the sum of its proper divisors (1).

497121247369 is an equidigital number, since it uses as much as digits as its factorization.

497121247369 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4572288, while the sum is 55.

The spelling of 497121247369 in words is "four hundred ninety-seven billion, one hundred twenty-one million, two hundred forty-seven thousand, three hundred sixty-nine".