Base | Representation |
---|---|
bin | 101110010011100001… |
… | …101010101010010111 |
3 | 11202100001102021221121 |
4 | 232103201222222113 |
5 | 1303311221412003 |
6 | 34501350024411 |
7 | 3410046421462 |
oct | 562341525227 |
9 | 152301367847 |
10 | 49719716503 |
11 | 1a0a45359a6 |
12 | 9777048107 |
13 | 48c49862c2 |
14 | 25994102d9 |
15 | 145ee7ccbd |
hex | b9386aa97 |
49719716503 has 2 divisors, whose sum is σ = 49719716504. Its totient is φ = 49719716502.
The previous prime is 49719716467. The next prime is 49719716531. The reversal of 49719716503 is 30561791794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49719716503 - 221 = 49717619351 is a prime.
It is a super-4 number, since 4×497197165034 (a number of 44 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49719716903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24859858251 + 24859858252.
It is an arithmetic number, because the mean of its divisors is an integer number (24859858252).
Almost surely, 249719716503 is an apocalyptic number.
49719716503 is a deficient number, since it is larger than the sum of its proper divisors (1).
49719716503 is an equidigital number, since it uses as much as digits as its factorization.
49719716503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1428840, while the sum is 52.
The spelling of 49719716503 in words is "forty-nine billion, seven hundred nineteen million, seven hundred sixteen thousand, five hundred three".
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