49719811 has 2 divisors, whose sum is σ = 49719812. Its totient is φ = 49719810.

The previous prime is 49719799. The next prime is 49719821. The reversal of 49719811 is 11891794.

49719811 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-49719811 is a prime.

It is a super-4 number, since 4×49719811⁴ (a number of 32 digits) contains 4444 as substring.

It is equal to p_2985295 and since 49719811 and 2985295 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (49719821) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24859905 + 24859906.

It is an arithmetic number, because the mean of its divisors is an integer number (24859906).

Almost surely, 2^49719811 is an apocalyptic number.

49719811 is a deficient number, since it is larger than the sum of its proper divisors (1).

49719811 is an equidigital number, since it uses as much as digits as its factorization.

49719811 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18144, while the sum is 40.

The square root of 49719811 is about 7051.2276236128. The cubic root of 49719811 is about 367.7137103657.

The spelling of 49719811 in words is "forty-nine million, seven hundred nineteen thousand, eight hundred eleven".