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49720009693 is a prime number
BaseRepresentation
bin101110010011100010…
…110010001111011101
311202100001222012010111
4232103202302033131
51303311310302233
634501400210021
73410052052324
oct562342621735
9152301865114
1049720009693
111a0a4716202
129777169911
1348c4a598a3
1425994890bb
15145eed9acd
hexb938b23dd

49720009693 has 2 divisors, whose sum is σ = 49720009694. Its totient is φ = 49720009692.

The previous prime is 49720009687. The next prime is 49720009727. The reversal of 49720009693 is 39690002794.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 45121406724 + 4598602969 = 212418^2 + 67813^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49720009693 is a prime.

It is a super-4 number, since 4×497200096934 (a number of 44 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49720009793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24860004846 + 24860004847.

It is an arithmetic number, because the mean of its divisors is an integer number (24860004847).

Almost surely, 249720009693 is an apocalyptic number.

It is an amenable number.

49720009693 is a deficient number, since it is larger than the sum of its proper divisors (1).

49720009693 is an equidigital number, since it uses as much as digits as its factorization.

49720009693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 734832, while the sum is 49.

The spelling of 49720009693 in words is "forty-nine billion, seven hundred twenty million, nine thousand, six hundred ninety-three".