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4973237451213 = 31657745817071
BaseRepresentation
bin100100001011110110000…
…0011010011100111001101
3122121102210110122210012120
41020113230003103213031
51122440142241414323
614324401310123153
71022206313564433
oct110275403234715
918542713583176
104973237451213
111648157986549
12683a1b1b04b9
132a0c88651395
141329c52b4d53
1589572e425e3
hex485ec0d39cd

4973237451213 has 4 divisors (see below), whose sum is σ = 6630983268288. Its totient is φ = 3315491634140.

The previous prime is 4973237451199. The next prime is 4973237451293. The reversal of 4973237451213 is 3121547323794.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4973237451213 - 210 = 4973237450189 is a prime.

It is a super-2 number, since 2×49732374512132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4973237451293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 828872908533 + ... + 828872908538.

It is an arithmetic number, because the mean of its divisors is an integer number (1657745817072).

Almost surely, 24973237451213 is an apocalyptic number.

It is an amenable number.

4973237451213 is a deficient number, since it is larger than the sum of its proper divisors (1657745817075).

4973237451213 is a wasteful number, since it uses less digits than its factorization.

4973237451213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1657745817074.

The product of its digits is 3810240, while the sum is 51.

The spelling of 4973237451213 in words is "four trillion, nine hundred seventy-three billion, two hundred thirty-seven million, four hundred fifty-one thousand, two hundred thirteen".

Divisors: 1 3 1657745817071 4973237451213