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4973307580841 is a prime number
BaseRepresentation
bin100100001011111000000…
…1110110101000110101001
3122121102222100121201222012
41020113300032311012221
51122440313220041331
614324412253205305
71022211124641125
oct110276016650651
918542870551865
104973307580841
111648193525a16
12683a3a790835
132a0c9a036bc2
141329d072c585
158957919682b
hex485f03b51a9

4973307580841 has 2 divisors, whose sum is σ = 4973307580842. Its totient is φ = 4973307580840.

The previous prime is 4973307580789. The next prime is 4973307580847. The reversal of 4973307580841 is 1480857033794.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2911869216400 + 2061438364441 = 1706420^2 + 1435771^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4973307580841 is a prime.

It is not a weakly prime, because it can be changed into another prime (4973307580847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486653790420 + 2486653790421.

It is an arithmetic number, because the mean of its divisors is an integer number (2486653790421).

Almost surely, 24973307580841 is an apocalyptic number.

It is an amenable number.

4973307580841 is a deficient number, since it is larger than the sum of its proper divisors (1).

4973307580841 is an equidigital number, since it uses as much as digits as its factorization.

4973307580841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20321280, while the sum is 59.

The spelling of 4973307580841 in words is "four trillion, nine hundred seventy-three billion, three hundred seven million, five hundred eighty thousand, eight hundred forty-one".