Base | Representation |
---|---|
bin | 101110010100011011… |
… | …001110001111010111 |
3 | 11202101002210211201001 |
4 | 232110123032033113 |
5 | 1303324102220224 |
6 | 34503045244131 |
7 | 3410321601565 |
oct | 562433161727 |
9 | 152332724631 |
10 | 49734804439 |
11 | 1a102000771 |
12 | 9780103647 |
13 | 48c7b39988 |
14 | 259b41aa35 |
15 | 146145d544 |
hex | b946ce3d7 |
49734804439 has 2 divisors, whose sum is σ = 49734804440. Its totient is φ = 49734804438.
The previous prime is 49734804421. The next prime is 49734804503. The reversal of 49734804439 is 93440843794.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49734804439 - 25 = 49734804407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49734804439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49734804739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24867402219 + 24867402220.
It is an arithmetic number, because the mean of its divisors is an integer number (24867402220).
Almost surely, 249734804439 is an apocalyptic number.
49734804439 is a deficient number, since it is larger than the sum of its proper divisors (1).
49734804439 is an equidigital number, since it uses as much as digits as its factorization.
49734804439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10450944, while the sum is 55.
The spelling of 49734804439 in words is "forty-nine billion, seven hundred thirty-four million, eight hundred four thousand, four hundred thirty-nine".
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