Base | Representation |
---|---|
bin | 101110010100111110… |
… | …010000100001010111 |
3 | 11202101202002110022102 |
4 | 232110332100201113 |
5 | 1303333430120243 |
6 | 34504014152315 |
7 | 3410462633324 |
oct | 562476204127 |
9 | 152352073272 |
10 | 49743988823 |
11 | 1a107204071 |
12 | 97831b269b |
13 | 48c9a04219 |
14 | 259c72bb4b |
15 | 14621749b8 |
hex | b94f90857 |
49743988823 has 2 divisors, whose sum is σ = 49743988824. Its totient is φ = 49743988822.
The previous prime is 49743988817. The next prime is 49743988843. The reversal of 49743988823 is 32888934794.
49743988823 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49743988823 - 216 = 49743923287 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49743988823.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49743988843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24871994411 + 24871994412.
It is an arithmetic number, because the mean of its divisors is an integer number (24871994412).
Almost surely, 249743988823 is an apocalyptic number.
49743988823 is a deficient number, since it is larger than the sum of its proper divisors (1).
49743988823 is an equidigital number, since it uses as much as digits as its factorization.
49743988823 is an evil number, because the sum of its binary digits is even.
The product of its digits is 83607552, while the sum is 65.
The spelling of 49743988823 in words is "forty-nine billion, seven hundred forty-three million, nine hundred eighty-eight thousand, eight hundred twenty-three".
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