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4974401341 = 713467117053
BaseRepresentation
bin1001010000111111…
…10101011100111101
3110211200012202210201
410220133311130331
540141421320331
62141334403501
7234161466550
oct45037653475
913750182721
104974401341
112122a13398
12b69b00591
13613768060
1435291a697
151e1a9ba61
hex1287f573d

4974401341 has 16 divisors (see below), whose sum is σ = 6135502464. Its totient is φ = 3927328704.

The previous prime is 4974401339. The next prime is 4974401353. The reversal of 4974401341 is 1431044794.

4974401341 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4974401341 - 21 = 4974401339 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4974401341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4974401321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16030 + ... + 101023.

It is an arithmetic number, because the mean of its divisors is an integer number (383468904).

Almost surely, 24974401341 is an apocalyptic number.

It is an amenable number.

4974401341 is a deficient number, since it is larger than the sum of its proper divisors (1161101123).

4974401341 is a wasteful number, since it uses less digits than its factorization.

4974401341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117540.

The product of its (nonzero) digits is 48384, while the sum is 37.

The square root of 4974401341 is about 70529.4359895214. The cubic root of 4974401341 is about 1707.0527462419.

The spelling of 4974401341 in words is "four billion, nine hundred seventy-four million, four hundred one thousand, three hundred forty-one".

Divisors: 1 7 13 91 467 3269 6071 42497 117053 819371 1521689 10651823 54663751 382646257 710628763 4974401341