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497463130093 is a prime number
BaseRepresentation
bin1110011110100110001…
…11001111011111101101
31202120001001122100221211
413033103013033133231
531122301030130333
61020310441154421
750640412560226
oct7172307173755
91676031570854
10497463130093
11181a77a715a6
12804b348ba11
1337bab6ac717
141a11233624d
15ce18072ecd
hex73d31cf7ed

497463130093 has 2 divisors, whose sum is σ = 497463130094. Its totient is φ = 497463130092.

The previous prime is 497463130039. The next prime is 497463130097. The reversal of 497463130093 is 390031364794.

Together with previous prime (497463130039) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 468604595209 + 28858534884 = 684547^2 + 169878^2 .

It is a cyclic number.

It is not a de Polignac number, because 497463130093 - 221 = 497461032941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (497463130097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248731565046 + 248731565047.

It is an arithmetic number, because the mean of its divisors is an integer number (248731565047).

Almost surely, 2497463130093 is an apocalyptic number.

It is an amenable number.

497463130093 is a deficient number, since it is larger than the sum of its proper divisors (1).

497463130093 is an equidigital number, since it uses as much as digits as its factorization.

497463130093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1469664, while the sum is 49.

The spelling of 497463130093 in words is "four hundred ninety-seven billion, four hundred sixty-three million, one hundred thirty thousand, ninety-three".