Base | Representation |
---|---|
bin | 100100001100110111111… |
… | …1011101001111000010101 |
3 | 122121122111200000211101020 |
4 | 1020121233323221320111 |
5 | 1123004210202202111 |
6 | 14325405025351353 |
7 | 1022315201345226 |
oct | 110315773517025 |
9 | 18548450024336 |
10 | 4975450037781 |
11 | 1649092922593 |
12 | 684338198559 |
13 | 2a124bb6b9c2 |
14 | 132b550ab24d |
15 | 896522e8906 |
hex | 4866fee9e15 |
4975450037781 has 8 divisors (see below), whose sum is σ = 6663681964800. Its totient is φ = 3302092401312.
The previous prime is 4975450037773. The next prime is 4975450037849. The reversal of 4975450037781 is 1877300545794.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4975450037781 - 23 = 4975450037773 is a prime.
It is a super-3 number, since 3×49754500377813 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4975450137781) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3718571856 + ... + 3718573193.
It is an arithmetic number, because the mean of its divisors is an integer number (832960245600).
Almost surely, 24975450037781 is an apocalyptic number.
It is an amenable number.
4975450037781 is a deficient number, since it is larger than the sum of its proper divisors (1688231927019).
4975450037781 is a wasteful number, since it uses less digits than its factorization.
4975450037781 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7437145275.
The product of its (nonzero) digits is 29635200, while the sum is 60.
The spelling of 4975450037781 in words is "four trillion, nine hundred seventy-five billion, four hundred fifty million, thirty-seven thousand, seven hundred eighty-one".
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