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49770433 = 411213913
BaseRepresentation
bin1011110111011…
…0111111000001
310110122121012101
42331312333001
5100220123213
64534430401
71143020206
oct275667701
9113577171
1049770433
1126104299
1214802401
13a407a7b
146877cad
154581bdd
hex2f76fc1

49770433 has 4 divisors (see below), whose sum is σ = 50984388. Its totient is φ = 48556480.

The previous prime is 49770421. The next prime is 49770463. The reversal of 49770433 is 33407794.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1495729 + 48274704 = 1223^2 + 6948^2 .

It is a cyclic number.

It is not a de Polignac number, because 49770433 - 25 = 49770401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49770392 and 49770401.

It is not an unprimeable number, because it can be changed into a prime (49770403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606916 + ... + 606997.

It is an arithmetic number, because the mean of its divisors is an integer number (12746097).

Almost surely, 249770433 is an apocalyptic number.

It is an amenable number.

49770433 is a deficient number, since it is larger than the sum of its proper divisors (1213955).

49770433 is a wasteful number, since it uses less digits than its factorization.

49770433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1213954.

The product of its (nonzero) digits is 63504, while the sum is 37.

The square root of 49770433 is about 7054.8162981044. The cubic root of 49770433 is about 367.8384633850.

The spelling of 49770433 in words is "forty-nine million, seven hundred seventy thousand, four hundred thirty-three".

Divisors: 1 41 1213913 49770433