Base | Representation |
---|---|
bin | 101110010111010111… |
… | …111000100000000101 |
3 | 11202111112212110211012 |
4 | 232113113320200011 |
5 | 1303424232314423 |
6 | 34512013252005 |
7 | 3411462142643 |
oct | 562727704005 |
9 | 152445773735 |
10 | 49784260613 |
11 | 1a127a0a93a |
12 | 9794794005 |
13 | 4905164699 |
14 | 25a3c12193 |
15 | 146597c078 |
hex | b975f8805 |
49784260613 has 2 divisors, whose sum is σ = 49784260614. Its totient is φ = 49784260612.
The previous prime is 49784260601. The next prime is 49784260639. The reversal of 49784260613 is 31606248794.
49784260613 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35996334529 + 13787926084 = 189727^2 + 117422^2 .
It is a cyclic number.
It is not a de Polignac number, because 49784260613 - 24 = 49784260597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49784260913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24892130306 + 24892130307.
It is an arithmetic number, because the mean of its divisors is an integer number (24892130307).
Almost surely, 249784260613 is an apocalyptic number.
It is an amenable number.
49784260613 is a deficient number, since it is larger than the sum of its proper divisors (1).
49784260613 is an equidigital number, since it uses as much as digits as its factorization.
49784260613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 50.
The spelling of 49784260613 in words is "forty-nine billion, seven hundred eighty-four million, two hundred sixty thousand, six hundred thirteen".
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