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497970113 is a prime number
BaseRepresentation
bin11101101011100…
…110101111000001
31021201000111120112
4131223212233001
52004440020423
6121225121105
715224450624
oct3553465701
91251014515
10497970113
11236100353
1211a929195
137c224194
144a1c7dbb
152dab6a78
hex1dae6bc1

497970113 has 2 divisors, whose sum is σ = 497970114. Its totient is φ = 497970112.

The previous prime is 497970059. The next prime is 497970131. The reversal of 497970113 is 311079794.

Together with next prime (497970131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 351487504 + 146482609 = 18748^2 + 12103^2 .

It is a cyclic number.

It is not a de Polignac number, because 497970113 - 222 = 493775809 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (497970173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248985056 + 248985057.

It is an arithmetic number, because the mean of its divisors is an integer number (248985057).

Almost surely, 2497970113 is an apocalyptic number.

It is an amenable number.

497970113 is a deficient number, since it is larger than the sum of its proper divisors (1).

497970113 is an equidigital number, since it uses as much as digits as its factorization.

497970113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47628, while the sum is 41.

The square root of 497970113 is about 22315.2439601273. The cubic root of 497970113 is about 792.6249876010.

The spelling of 497970113 in words is "four hundred ninety-seven million, nine hundred seventy thousand, one hundred thirteen".