Base | Representation |
---|---|
bin | 101110011000010110… |
… | …100010000000100101 |
3 | 11202112200202211212101 |
4 | 232120112202000211 |
5 | 1303442433333212 |
6 | 34513401252101 |
7 | 3412051553152 |
oct | 563026420045 |
9 | 152480684771 |
10 | 49800683557 |
11 | 1a136207719 |
12 | 979a194031 |
13 | 49086948c1 |
14 | 25a6089229 |
15 | 1467123157 |
hex | b985a2025 |
49800683557 has 2 divisors, whose sum is σ = 49800683558. Its totient is φ = 49800683556.
The previous prime is 49800683519. The next prime is 49800683587. The reversal of 49800683557 is 75538600894.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46586473921 + 3214209636 = 215839^2 + 56694^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49800683557 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49800683498 and 49800683507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49800683587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24900341778 + 24900341779.
It is an arithmetic number, because the mean of its divisors is an integer number (24900341779).
Almost surely, 249800683557 is an apocalyptic number.
It is an amenable number.
49800683557 is a deficient number, since it is larger than the sum of its proper divisors (1).
49800683557 is an equidigital number, since it uses as much as digits as its factorization.
49800683557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 55.
The spelling of 49800683557 in words is "forty-nine billion, eight hundred million, six hundred eighty-three thousand, five hundred fifty-seven".
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